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Code Issues Releases Wiki Activity

As mentioned in commit message for 12574, here is one example of a routine

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that was doing extra processing because Dither couldn't return interleaved
buffers.
This commit is contained in:
lllucius
2013-09-22 06:26:06 +00:00
parent a3d27b135b
commit 7ddd4ed2ab
1 changed files with 10 additions and 16 deletions
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22
src/AudioIO.cpp
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@@ -3217,25 +3217,19 @@ static void DoSoftwarePlaythrough(const void *inputBuffer,
float *outputBuffer, float *outputBuffer,
int len) int len)
{ {
float *tempBuffer = (float *)alloca(len * sizeof(float)); for (int i=0; i < inputChannels; i++) {
int i, j; samplePtr inputPtr = ((samplePtr)inputBuffer) + (i * SAMPLE_SIZE(inputFormat));
samplePtr outputPtr = ((samplePtr)outputBuffer) + (i * SAMPLE_SIZE(floatSample));
for(j=0; j<inputChannels; j++) {
samplePtr inputPtr = ((samplePtr)inputBuffer) + (j * SAMPLE_SIZE(inputFormat));
CopySamples(inputPtr, inputFormat, CopySamples(inputPtr, inputFormat,
(samplePtr)tempBuffer, floatSample, (samplePtr)outputPtr, floatSample,
len, true, inputChannels); len, true, inputChannels, 2);
}
for(i=0; i<len; i++)
outputBuffer[2*i + (j%2)] = tempBuffer[i];
// One mono input channel goes to both output channels... // One mono input channel goes to both output channels...
if (inputChannels == 1) if (inputChannels == 1)
for(i=0; i<len; i++) for (int i=0; i < len; i++)
outputBuffer[2*i + 1] = tempBuffer[i]; outputBuffer[2*i + 1] = outputBuffer[2*i];
}
} }
int audacityAudioCallback(const void *inputBuffer, void *outputBuffer, int audacityAudioCallback(const void *inputBuffer, void *outputBuffer,